k^2/18-k/18-20/18

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Solution for k^2/18-k/18-20/18 equation: 


k in (-oo:+oo)

(k^2)/18-(k/18)-(20/18) = 0

(k^2)/18-(k/18)-10/9 = 0

1/18*k^2-1/18*k-10/9 = 0

DELTA = (-1/18)^2-(-10/9*1/18*4)

DELTA = 1/4

DELTA > 0

k = ((1/4)^(1/2)+1/18)/(1/18*2) or k = (1/18-(1/4)^(1/2))/(1/18*2)

k = 5 or k = -4

k in { -4, 5 }

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